contestada

7. A monkey freefalls for 17.5 seconds. (a) What was the velocity after this time? (b) How far did it fall?

Respuesta :

Answer:

a ) Vf = 171.7 [m/s]

b) y = 1502.6[m]

Explanation:

a) To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}+g*t[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (freefall, without initial velocity)

g = gravity acceleration = 9.81 [m/s²]

t = time = 17.5 [s]

Now replacing:

[tex]v_{f} = 0 + 9.81*17.5\\v_{f} = 171.7[m/s][/tex]

Note: The gravity acceleration is positive, since the monkey is moving in the direction of the gravity acceleration.

b)

Now using another equation of kinematics we can calculate the distance traveled.

[tex]v_{f}^{2}=v_{o}^{2}+2*g*y[/tex]

where:

y = distance traveled [m]

[tex]171.7^{2}=0 +2*9.81*y\\y=29480.9/(2*9.81)\\y=1502.6[m][/tex]