1.Find the compound interest on Rs25000 for 3 years at 10% per annum ,Compounded annually.
Plzz answer this question in step by step explanation.

Respuesta :

Answer:

The compound interest is Rs8275

Step-by-step explanation:

The rule of the compound interest is A = P[tex](1+\frac{r}{n})^{nr}[/tex], where

  • A is the new amount
  • P is the initial amount
  • r is the interest rate in decimal
  • n is the number of periods
  • t is the time

The interest I = A - P

∵ The amount of investment is Rs25000 for 3 years

P = 25000

t = 3

∵ The rate of interest is 10% per annum, compounded annually

r = 10% = 10 ÷ 100 = 0.1

n = 1 ⇒ compounded annually

→ Substitute these value in the 1st rule above to find the new amount

∵ A = 25000[tex](1+\frac{0.1}{1})^{1(3)}[/tex]

∴ A = 25000[tex](1.1)^{3}[/tex]

A = Rs33275

→ Use the 2nd rule above to find the interest

I = 33275 - 25000

∴ I = 8275

The compound interest is Rs8275