Answer:
f(x) = ax^5 + bx^3 + cx^2 + 12.
Step-by-step explanation:
the degree is 5 so we will have a term like:
ax^5
it crosses the vertical axis at y = 12 so we will have a constant term equal to 12
the polynomial has 4 terms, and we already have two so we can make up two more but the exponent must be between 1 and 4
f(x) = ax^5 + bx^3 + cx^2 + 12.
it has 4 terms, f(0) = 12, then it intersects the y-axis at y = 12, and the maximum exponent is 5, then the degree of f(x) is 5
