Answer:
The value is [tex]r = 0.39279 \ m[/tex]
Explanation:
From the question we are told that
The first point charge is [tex]q_1 = 60.0 \mu C = 60 *10^{-6} \ C[/tex]
The second point charge is [tex]q_2 = 50 \mu C = 50 *10^{-6} \ C[/tex]
The repulsive force exerted is [tex]F = 175 \ N[/tex]
Generally the repulsive force exerted is mathematically represented as
[tex]F = \frac{k * q_1 * q_2 }{r^2}[/tex]
Here k is the coulomb constant with a value [tex]k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]
So
[tex]r = \sqrt{\frac{ k * q_1 * q_2 }{F} }[/tex]
=> [tex]r = \sqrt{\frac{ 9*10^9 * 60 *10^{-6} * 50 *10^{-6}}{175} }[/tex]
=> [tex]r = 0.39279 \ m[/tex]
