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A spacecraft's landing is cushioned by air bags. As it lands on Mars, the velocity of downward fall is 20 meters/second. Immediately after impact the velocity is 10 meters/second. If the spacecraft has a mass of 7.1 × 104 kilograms, what is the value of the impulse?

Respuesta :

Thank you for posting your question here in brainly. Below are the choices that can be found elsewhere.

A. 1.2 x 10^4
B. 2.2 x 10^5
C. 7.1 x 10^5
D. 3.6 x 10^4

The answer is C that means to say that the velocity after impact is still in the same direction as when the spaceship is falling.

Answer: The value of impulse will be [tex]7.1\times 10^5kg.m/s[/tex]

Explanation:

Impulse is defined s the change in the momentum.

Mathematically,

[tex]\text{Impulse}=m\Delta v[/tex]

where,

m = Mass of the object

[tex]\Delta v[/tex] = Change in the velocity = [tex]v_2-v_1[/tex]

Putting values in above equation, we get:

[tex]\text{impulse}=7.1\times 10^4kg(20-10)m/s=7.1\times 10^5kg.m/s[/tex]

Hence, the value of impulse is [tex]7.1\times 10^5kg.m/s[/tex]

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