Respuesta :

Cathenna

Answer:

[tex] \rm b = \dfrac{2A }{h} [/tex]

Step-by-step explanation:

[tex] \rm Solve \: for \: b: \\ \rm \longrightarrow A = \dfrac{1}{2} bh \\ \\ \rm A = \dfrac{bh}{2} \: is \: equivalen t \: to \: \dfrac{bh}{2} = A: \\ \rm \longrightarrow \dfrac{bh}{2} = A \\ \\ \rm Divide \: both \: sides \: by \: \dfrac{h}{2} : \\

\rm \longrightarrow \dfrac{bh}{2} \div \dfrac{h}{2} = A \div \dfrac{h}{2} \\ \\ \rm \longrightarrow \dfrac{bh}{2} \times \dfrac{2}{h} = A \times \frac{2}{h} \\ \\ \rm \dfrac{bh}{2} \times \dfrac{2}{h} = b : \\ \rm \longrightarrow b = \dfrac{2A }{h}[/tex]

FadedElla

Answer:

b in terms of A and h will be:

[tex] \boxed{ \rm{b = \frac{2A}{h} }}[/tex]

Step-by-step explanation:

This is basically the formula for finding the area(A) of the triangle in terms of b and h. We have to solve for b in terms of A and h.

[tex] \rm{A = \dfrac{1}{2} bh}[/tex]

Multiplying 2 in the LHS. This is shift because inverse of division is multiplication.

[tex] \rm{2A = bh}[/tex]

Dividing h from both sides,

[tex] \rm{b = \dfrac{2A}{h} }[/tex]

And we are done! :D

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