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Suppose a 125 N force is applied to a lawnmower handle at an angle of 35° with the ground and the lawnmower moves along the surface of the ground. If the lawnmower moves 56 m, how much work was done? (hint: use cos to find the x of force vector)

Respuesta :

Lanuel

Answer:

Workdone is 5734.06Nm.

Explanation:

Given the following data;

Force applied = 125N

Angle = 35°

Distance = 56m

To find the workdone by the lawnmower, we would first of all find the horizontal component of the force applied.

[tex] Horizontal force, Fx = mgCosd[/tex]

Where;

  • Fx represents the horizontal force.
  • m is the mass of an object.
  • g is the acceleration due to gravity.
  • d is the angle of inclination (theta).

mg = weight = 125N

Substituting into the equation, we have;

[tex] Fx = 125 * Cos35[/tex]

[tex] Fx = 125 * 0.8192[/tex]

Fx = 102.39N

Workdone is given by the formula;

[tex] Workdone = force * distance[/tex]

[tex] Workdone = 102.39 * 56[/tex]

Workdone = 5734.06Nm

Therefore, the work done by the lawnmower is 5734.06Nm.

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