Answer:
2nd option; [tex]c=9-a+b[/tex]
Step-by-step explanation:
- The first thing you need to do, is rewrite the equation without the square root.
- So for instance [tex]\sqrt{16}=4[/tex] and [tex]16=(4)^2[/tex] therefore [tex]a-b+c=(3)^2[/tex]
- Then [tex]a-b+c=9[/tex]
- Now we take away ' [tex]a[/tex] ' on both sides and add ' [tex]b[/tex] ' on both sides
- So [tex]a-(a)-b+(b)+c=9-(a)+(b)[/tex]
- Which gives us [tex]0+0+c=9-a+b[/tex] which is simply [tex]c=9-a+b[/tex]
Hope this helps
