Answer:
The maximum height reached by the projectile is 33.34 m
Explanation:
Given;
initial velocity of the projectile, u = 37 m/s
angle of projection, θ = 43.7°
The maximum height reached by the projectile = ?
Apply the following kinematic equation, to determine the maximum height reached by the projectile.
Maximum height (H) is given as;
[tex]H = \frac{u^2 sin^2\theta}{2g}\\\\ H = \frac{(37)^2 (sin 43.7)^2}{2*9.8}\\\\H = 33.34 \ m[/tex]
Therefore, the maximum height reached by the projectile is 33.34 m