The linear speed of the ladybug is 4.1 m/s
Explanation:
First of all, we need to find the angular speed of the lady bug. This is given by:
[tex]\omega=\frac{2\pi}{T}[/tex]
where
T is the period of revolution
The period of revolution is the time taken by the ladybug to complete one revolution: in this case, since it does 1 revolution every second, the period is 1 second:
T = 1 s
Therefore, the angular speed is
[tex]\omega=\frac{2\pi}{1 s}=6.28 rad/s[/tex]
Now we can find the linear speed of the ladybug, which is given by
[tex]v=\omega r[/tex]
where:
[tex]\omega=6.28 rad/s[/tex] is the angular speed
r = 65.0 cm = 0.65 m is the distance of the ladybug from the axis of rotation
Substituting, we find
[tex]v=(6.28)(0.65)=4.1 m/s[/tex]
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