A lady bug is sitting on the bottom of a can while you twirl it overhead on a string that is 65.0
cm long. If you twirl the can around 1 once every second, how fast is the bug moving?

Respuesta :

The linear speed of the ladybug is 4.1 m/s

Explanation:

First of all, we need to find the angular speed of the lady bug. This is given by:

[tex]\omega=\frac{2\pi}{T}[/tex]

where

T is the period of revolution

The period of revolution is the time taken by the ladybug to complete one revolution: in this case, since it does 1 revolution every second, the period is 1 second:

T = 1 s

Therefore, the angular speed is

[tex]\omega=\frac{2\pi}{1 s}=6.28 rad/s[/tex]

Now we can find the linear speed of the ladybug, which is given by

[tex]v=\omega r[/tex]

where:

[tex]\omega=6.28 rad/s[/tex] is the angular speed

r = 65.0 cm = 0.65 m is the distance of the ladybug from the axis of rotation

Substituting, we find

[tex]v=(6.28)(0.65)=4.1 m/s[/tex]

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