Respuesta :
Answer:
The equilibrium concentration of NO is 0.02124 M.
Explanation:
Given that,
Initial concentration of NOBr = 0.878 M
[tex]k_{c}=3.07\times10^{-4}[/tex]
Temperature = 24°C
We know that,
The balance equation is
[tex]2NOBr\Rightarrow 2NO+Br_{2}[/tex]
Initial concentration is,
[tex]0.878\Rightarrow 0+0[/tex]
Concentration is,
[tex]-2x\Rightarrow 2x+x[/tex]
Equilibrium concentration
[tex]0.878-2x\Rightarrow 2x+x[/tex]
We need to calculate the value of x
Using formula of concentration
[tex]k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}[/tex]
Put the value into the formula
[tex]3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}[/tex]
[tex]2x^2=3.07\times10^{-4}\times(0.878)^2+3.07\times10^{-4}\times4x^2-2\times2x\times0.878\times3\times10^{-4}[/tex]
[tex]2x^2=0.0002367+0.001228x^2-0.0010536x[/tex]
[tex]2x^2-0.001228x^2+0.0010536x-0.0002367=0[/tex]
[tex]1.998772x^2+0.0010536x-0.0002367=0[/tex]
[tex]x=0, 0.01062[/tex]
We need to calculate the equilibrium concentration of NO
Using formula of concentration of NO
[tex]concentration\ of\ NO=2x[/tex]
Put the value of x
[tex]concentration\ of\ NO=2\times0.01062[/tex]
[tex]concentration\ of\ NO=0.02124[/tex]
Hence, The equilibrium concentration of NO is 0.02124 M.
