Graph the line with slope of 53
5/3 and goes through the point (2,1).

Answer:
We kindly invite you to see the image attached for further details.
Step-by-step explanation:
From Analytical Geometry we get that linear functions can be found after knowing a point and its slope. The standard form of a linear function is represented by the following formula:
[tex]y =m\cdot x +b[/tex] (Eq. 1)
Where:
[tex]x[/tex] - Independent variable, dimensionless.
[tex]y[/tex] - Dependent variable, dimensionless.
[tex]m[/tex] - Slope, dimensionless.
[tex]b[/tex] - y-Intercept, dimensionless.
At first we need to calculate the y-Intercept, which is cleared within (Eq. 1):
[tex]b = y-m\cdot x[/tex]
If we know that [tex]y = 1[/tex], [tex]x = 2[/tex] and [tex]m = \frac{5}{3}[/tex], then the y-Intercept of the linear function is:
[tex]b = 1-\left(\frac{5}{3} \right)\cdot (2)[/tex]
[tex]b = -\frac{7}{3}[/tex]
Line with a slope of [tex]\frac{5}{3}[/tex] that goes through the point (2, 1) is represented by [tex]y = \frac{5}{3}\cdot x -\frac{7}{3}[/tex].
Lastly, we graph the line by using a plotting software (i.e. Desmos), whose result is included below as attachment.