Respuesta :
m(slope)= -5/4 point-slope(y-y1=m(x-x1)) so it would be y-5= -5/4(x+4)
The slope is -5/4 and the equation of the line in point-slope form is y-5 = -5/4(x+4) + c.
What is slope of a line?
The slope or gradient of a line is a number that describes both the direction X and Y and the steepness of the line. It is the ratio of the vertical change to the horizontal change between any two distinct points on a line.
For the given situation,
The points are (x1,y1) is (−4,5) and (x2,y2) is (0,0)
The formula of slope is
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
⇒ [tex]m=\frac{0-5}{0-(-4)}[/tex]
⇒ [tex]m=\frac{-5}{4}[/tex]
The equation of the line in point-slope form is
[tex]y-y1=m(x-x1)[/tex]
⇒ [tex]y-5=\frac{-5}{4} (x-(-4))[/tex]
⇒ [tex]y-5=\frac{-5}{4} (x+4)[/tex]
Hence we can conclude that the slope is -5/4 and the equation of the line in point-slope form is y-5 = -5/4 (x+4).
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