Answer:
Step-by-step explanation:
[tex]\left|x+6\right|=\left|x-12\right|\\\\\mathrm{For\:each\:absolute\:find\:positive\:and\:negative\:intervals}\\ \\\mathrm{For\:}x<-6:\quad \mathrm{No\:Solution}\\\\\mathrm{For\:}-6\le \:x<12:\quad x=3\\\\\mathrm{For\:}x\ge \:12:\quad \mathrm{No\:Solution}\\\\\mathrm{Combine\:Solutions:}\\\\\mathrm{No\:Solution}\quad \mathrm{or}\quad \:x=3\\\\x=3[/tex]
