Given :
Height of a falling object t seconds after being dropped from a height of 262 feet is given by f(t)= 262-16t^2 feet.
To Find :
The average velocity between times t=3 and t=4 s .
Solution :
Velocity is given by :
[tex]V=\dfrac{df}{dt}=-32t[/tex]
Now , average velocity is given by :
[tex]V_{avg}=\dfrac{V_4-V_3}{4-3}\\\\V_{avg}=\dfrac{(-32)(4)-(-32)(3)}{1}\\\\V_{avg}= -32\ feet/sec[/tex]
Hence , this is the required solution .
