Answer:
x = 4[tex]\sqrt{3}[/tex] in
Step-by-step explanation:
Given a tangent and a secant to the circle from an external point, then
The square of the tangent is equal to the product of the secant's external part and the entire secant, that is
x² = 4(4 + 8) = 4 × 12 = 48 ( take the square root of both sides )
x = [tex]\sqrt{48}[/tex] = [tex]\sqrt{16(3)}[/tex] = [tex]\sqrt{16}[/tex] × [tex]\sqrt{3}[/tex] = 4[tex]\sqrt{3}[/tex] ← exact value
