Answer:
Explanation:
Acceleration is the change in velocity of a body with respect to time.
a = Δv/Δt
a = v-u/t₂-t₁
v is the final velocity
u is the initial velocity
t₂ is the final time
t₁ is the initial time
To calculate the average acceleration of the object between t=2 s and t=6 s, we will get the equivalent velocity of the body during this times from the graph shown in the attachment.
At t₁ = 2s, u = 3m/s
at t₂ = 6s, v = 5m/s
Substitute the given parameters into the formula for calculating acceleration;
[tex]a = \dfrac{5-3}{6-2}\\ \\a = \dfrac{2}{4} \\\\a = \dfrac{1}{2} \\\\a = 0.5m/s^{2}[/tex]
Hence the average acceleration of the object between t=2 s and t=6 s is 0.5m/s²
