Answer:
45 different permutations
Step-by-step explanation:
Given 10 letters with 8 identical H's and two identical T's, the number of different permutations will be expressed as;
[tex]= \dfrac{10!}{8!2!}[/tex]
[tex]= \dfrac{10*9*8!}{8!*2!}\\ \\= \dfrac{10*9}{2*1}\\ \\= \dfrac{90}{2}\\ \\= 45[/tex]
Hence the number of different 10-letter permutations that can be formed from 8 identical H's and two identical T's is 45
