Answer:
5.
[tex]\left(8-6\right)^5\cdot \:2^{-4}+2^0[/tex]
Subtract 8 - 6 = 2:
[tex](2)^5\cdot \:2^{-4}+2^0[/tex]
Anything to the power of 0 is 1. (Except 0):
[tex]2^5\cdot \:2^{-4}+1[/tex]
Multiply:
[tex]2^{5-4}+1[/tex]
[tex]2^1+1[/tex]
[tex]2+1[/tex]
[tex]3[/tex]
6.
[tex]\frac{\left(9-1\right)^5}{\left(6+2\right)^3}[/tex]
Solve the brackets: 9 - 1 = 8 and 6 + 2 = 8:
[tex]\frac{8^5}{8^3}[/tex]
[tex]8^{5-3}[/tex]
[tex]8^2[/tex]
(or [tex]64[/tex] for exact value)
