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PLEASE ANSWER QUICK Part A: If (62)x = 1, what is the value of x? Explain your answer. (5 points) Part B: If (60)x = 1, what are the possible values of x? Explain your answer. (5 points)

PLEASE ANSWER QUICK Part A If 62x 1 what is the value of x Explain your answer 5 points Part B If 60x 1 what are the possible values of x Explain your answer 5 class=

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HiImMickeyMouse

Answer:

The first one is 0, the second one is ARN (All real numbers)

Step-by-step explanation:

1. Anything raised to the "zeroth" power is always 1

2. Because 7 is being raised to the zeroth power, the number inside the parentheses becomes 1. Now x can equal anything, 1 times itself will always equal 1, no matter how many times you multiply them.

MrRoyal

Equations can have one, zero or infinitely many solutions.

  • a: The value of x is 0
  • b: x has infinitely many solutions

[tex](a)\ (6^2)^x = 1[/tex]

Express 1 as [tex]6^0[/tex]

[tex](6^2)^x = 6^0[/tex]

Express 0 as 2 x 0

[tex](6^2)^x = 6^{2 \times 0}[/tex]

Open the bracket

[tex]6^{2 \times x} = 6^{2 \times 0}[/tex]

Cancel out 6 on both sides

[tex]2 \times x =2 \times 0[/tex]

Divide both sides by 2

[tex]x =0[/tex]

Hence, the value of x is 0

[tex](b)\ (6^0)^x = 1[/tex]

Express [tex]6^0[/tex] as 1

[tex]1^x = 1[/tex]

Express [tex]1^x[/tex] as 1

[tex]1 = 1[/tex]

Both sides of the equation are the same

This means that:

x has infinitely many solutions

Read more about equations at:

https://brainly.com/question/10628783

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