Answer:
[tex](x^{2}-9)(x^{2} -1)[/tex]
Step-by-step explanation:
Step 1: Find what adds to _ and multiples to_
It needs to multiple to the 'c' term or 9
It needs to add to the 'b' term or -10
Step 2: Find the numbers
We know -9 and -1 make 10 and multiple to 9
-9 x -1 = 9
-9 + (-1) + -10
Step 3: Write equation in form a(x-r)(x-s)
a = 1
r = -9
s = -1
Plug in the equation to get the factored form of the equation:
[tex](x^{2}-9)(x^{2} -1)[/tex]
Therefore the factored form of the equation is [tex](x^{2}-9)(x^{2} -1)[/tex]
Quadratic equations are also a type of algebraic fractions that have factors.
The factor of [tex]x^{4} - 10x^{2} + 9 = (x -3)(x + 3)(x - 1)(x + 1)[/tex]
In order to completely factor [tex]x^{4} - 10x^{2} + 9[/tex] we would apply the formula:
a(x-r)(x-s)
To find the variables a, x, r and s, we have to love at the coefficients of [tex]x^{2}[/tex] which is -10 and the term 9 and find out what can we multiply together to give us 9 and add together to give us -10
That would be , -9 and - 1 because:
-9 x -1 = 9
-9 + (-1) = -10
Hence: the value for a = 1
, r = -9 and s = -1
Putting this into the equation:
1(x -(-9)(x - (-1))
Hence, we have:
[tex](x^2-9)( x^{2} - 1)[/tex]
Factorizing the above expression further, we have
[tex](x - 3)(x + 3)(x - 1)(x + 1)[/tex]
Therefore, the factor of [tex]x^{4} - 10x^{2} + 9 = (x -3)(x + 3)(x - 1)(x + 1)[/tex]
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https://brainly.com/question/22763163
