Respuesta :
Question is incomplete, The complete question is as follows:
When a bacterium such as E. coli is shifted from a warmer growth temperature to a cooler growth temperature, it compensates by:
A) increasing its metabolic rate to generate more heat.
B) putting longer-chain fatty acids into its membranes.
C) putting more unsaturated fatty acids into its membranes.
D) shifting from aerobic to anaerobic metabolism.
E) synthesizing thicker membranes to insulate the cell.
Answer:
C) putting more unsaturated fatty acids into its membranes.
Explanation:
Bacteria has the ability to change the composition of fatty acid present in its cell membrane to compensate the change in temperature.
When bacterium E.Coli will shift from hight or warmer temperature to low or cooler temperature, it will put more unsaturated fatty acids into its membranes which will mintain the fluidity in the membrane.
Hence, the correct option is "C".
