Given: Parallelogram LMNO; MO ⊥ LN Prove: LMNO is a rhombus. Parallelogram L M N O is shown. Diagonals are drawn from point L to point N and from point M to point O and intersect at point P. A square is drawn around point P. Sides L M and O N are parallel and sides L O and M N are parallel. ♣: ♦: ♠: I WILL GIVE BRAINLIEST PLS ANSWER

Respuesta :

The proofing is as follows:

Given that,

|LO|=|MN| and |LM|=|ON|

It means that  Opposite sides of a parallelogram are equa

Now, LN⊥OM

So,

∠LPO = ∠NPO = 90° ( by definition of perpendicular lines)

LPO ≅ ∠NPO (by definition of congruent angles)

|LP|=|PN| (diagonals of a parallelogram bisect each other)

based on this LMNO is a rhombus

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Answer:

All right angles are congruent

Reflexive property

Opposite sides of a parallelogram are congruent

Step-by-step explanation:

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