Answer : The interconnect resistance will be, 35250 Ω
Explanation :
The formula used to calculate the interconnect resistance is:
[tex]R=\rho \frac{L}{A}\\\\R=\rho \frac{L}{TW}[/tex]
where,
R = resistance = ?
L = length of wire = 1000 μm = 1000 × 10⁻⁶ m
T = thickness of wire = 40 nm = 40 × 10⁻⁹ m
W = width of wire = 20 nm = 20 × 10⁻⁹ m
[tex]\rho[/tex] = resistivity of aluminum = 2.82 × 10⁻⁸ Ωm
A = area
Now put all the given values in the above formula, we get:
[tex]R=(2.82\times 10^{-8}\Omega m)\times \frac{1000\times 10^{-6}m}{(40\times 10^{-9}m)\times (20\times 10^{-9}m)}[/tex]
[tex]R=35250\Omega[/tex]
Thus, the interconnect resistance will be, 35250 Ω
