Answer:
The force exerted on the instrument is [tex]N =79.6 \ N[/tex]
Explanation:
From the question we are told that
The mass of the instrument is [tex]m_i = 6.5 \ kg[/tex]
The height attained is [tex]H = 276 \ m[/tex]
The time taken is [tex]t = 15.0 \ s[/tex]
Now applying equation of motion we have that
[tex]H = u t + \frac{1}{2} at^2[/tex]
Now the space shuttle is accelerating from rest thus u= 0m/s
So
[tex]276 = 0 * (t) + 0.5 * a(15)^{2}[/tex]
[tex]a = 2.453 m/s ^2[/tex]
Now looking at the question we can deduce that the weight of the instrument is downward and the reaction force of the wire(N) is upward
So this can be mathematically be represented as
[tex]mg - N = ma[/tex]
Thus [tex]N = m(a+g )[/tex]
substituting values
[tex]N =6.5 * (2.453+9.8 )[/tex]
[tex]N =79.6 \ N[/tex]
