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A 13,500 kg railroad freight car travels on a level track at a speed of 4.5 m/s. It collides and couples with a 25,000 kg second car, initially at rest and with brakes released. What is the speed of the two cars after collision?

Respuesta :

nobleswift

Answer:

V = 1.578m/s

Explanation:

(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V

(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V

60750 + 0 = (38500)V

60750 = 38500V

V = 60750/38500

V = 1.578m/s

shubhamchouhanvrVT

The speed of the two cars after the collision will be equal to V = 1.578m/s

What is collision?

A collision is any event in which two or more bodies exert forces on each other in a relatively short time. Although the most common use of the word collision refers to incidents in which two or more objects collide with great force, the scientific use of the term implies nothing about the magnitude of the force

Now from the perfectly inelastic collision, the conservation of momentum will be

(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V

(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V

60750 + 0 = (38500)V

60750 = 38500V

V = 60750/38500

V = 1.578m/s

Hence the speed of the two cars after the collision will be equal to V = 1.578m/s

To know more about Collisions follow

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