Answer:
0.255
Explanation:
The following data were obtained from the question:
Force (F) = 57 N
Mass (m) = 22.8 Kg
Coefficient of static friction (µ) =...?
Next, we shall determine the normal reaction (R). This is illustrated below:
Mass (m) = 22.8 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (R) =?
R = mg
R = 22.8 x 9.8
R = 223.44 N
Finally, we can obtain the coefficient of static friction (µ) as follow:
Force (F) = 57 N
Normal reaction (R) = 223.44 N
Coefficient of static friction (µ) =...?
F = µR
57 = µ x 223.44
Divide both side by 223.44
µ = 57/223.44
µ = 0.255
Therefore, the coefficient of static friction (µ) is 0.255.
