Answer:
[tex]4x^{6}2y^{-2}[/tex]
Step-by-step explanation:
We can use a property I like to call SEi-F. (Subtract Exponents in a Fraction)
But first, there is an exponent outside of the parentheses in both places. We can use the Power of Parentheses to simplify and then use the SEi-F.
We will start with the x in the numerator.
3*4 = 12
Now for the y in the numerator.
4*4 = 16
Our new numerator is [tex]4(2x^{12}y^{16})[/tex]
We do need to simplify the numerator one more time to get rid of the 4 outside the parentheses.
We will start with x's coefficient.
2*4 = 8
Now for y's coefficient.
1**4 = 4
*y seems to have no coefficient, but if so, it has a coefficient of 1. This applies to other variables.
Our final simplified numerator is [tex]8x^{12}4y^{16}[/tex].
Repeat with the denominator.
Try it yourself!
Make sure that when you finish, you finish the fraction.
After completing the denominator, your completed fraction should be:
[tex]\frac{8x^{12}4y^{16}}{4x^{6}2y^{18}}[/tex]
Now we can use the SEi-F to complete the problem.
Start with x.
8x - 4x = 4x
12 - 6 = 6
The first term is [tex]4x^{6}[/tex].
Now for y.
4y - 2y = 2y
16 - 18 = -2
The second term is [tex]2y^{-2}[/tex]
The complete, simplified equation is [tex]4x^{6}2y^{-2}[/tex].
I could be wrong on the answer, but the work should be correct.
Hope this helps. Have a nice day. Oh, and one more thing. Surprised I'm not stealing points?
