Answer:
Option (2)
Step-by-step explanation:
This question is incomplete; find the picture attached which makes this question complete.
Vertices of the given triangle are A(-2, -4), B(2, -1) and C(3, -4).
Length of AB = [tex]\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]
AB = [tex]\sqrt{(2+2)^2+(-1+4)^2}[/tex]
= [tex]\sqrt{16+9}[/tex]
= 5 units
Since AB = AC
AC = 5 units
Similarly, BC = [tex]\sqrt{(3-2)^2+(-4+1)^2}[/tex]
BC = [tex]\sqrt{10}[/tex] units
Therefore, perimeter of the given triangle = AB + AC + BC
= 5 + 5 + √10
= (10 + √10) units
Option (2) will be the answer.
