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A salt has the formula AB2, and a Ksp value of 4.3 × 10-7. What is the solubility of the salt? A. 6.5 × 10-3 Molar B. 4.8 × 10-4 Molar C. 4.8 × 10-3 Molar D. 7.5 × 10-3 Molar

Respuesta :

Answer: The solubility of the salt is [tex]4.8\times 10^{-3}M[/tex]

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]

The equation for the reaction will be as follows:

[tex]AB_2\rightleftharpoons A^{2+}+2B^-[/tex]

By Stoichiometry,

1 mole of [tex]AB_2[/tex] gives 1 mole of [tex]A^{2+}[/tex] and 2 moles of [tex]B^-[/tex]

Thus if solubility of [tex]AB_2[/tex] is s moles/liter, solubility of [tex]A^{2+}[/tex] is s moles\liter and solubility of [tex]B^-[/tex] is 2s moles/liter

Therefore,  

[tex]K_sp=[A^{2+}][B^{-}]^2[/tex]

[tex]4.3\times 10^{-7}=[s][2s]^2[/tex]

[tex]4s^3=4.3\times 10^{-7}[/tex]

[tex]s=4.8\times 10^{-3}M[/tex]

The solubility of the salt is [tex]4.8\times 10^{-3}M[/tex]

Answer:

C. 4.8 x 10 -3

Explanation:

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