Answer:
50%
Explanation:
Step 1: Calculate the mass of water
Since we don't know the actual temperature at which the solution is prepared, we will assume the density of water is about 1 g/mL.
[tex]25mL \times \frac{1g}{1mL} = 25g[/tex]
Step 2: Calculate the mass of the solution
The mass of the solution is the sum of the mass of the solute (Iron (III) hydroxide) and the mass of the solvent (water).
[tex]m(solution) = m(solute) + m(solvent)\\m(solution) = 25 g + 25 g = 50g[/tex]
Step 3: Calculate the percent by mass of Iron (III) hydroxide in the solution
[tex]\frac{m(Fe(OH)_3)}{m(solution)} \times 100\% = \frac{25g}{50g} \times 100\% = 50\%[/tex]
