Which choice shows a function with a domain of {–4, –2, 2, 4}? On a coordinate plane, a vertical line is at x = 2. On a coordinate plane, a line goes through (negative 2, negative 2) and (0, negative 3). {(–4, 2), ( –2, 1), (2, 0), (4, 5)} {(1, –4), (0, –2), (2, 2), (6, 4)}

Respuesta :

Answer:

[tex]\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}[/tex]

Step-by-step explanation:

Given: Domain of function is [tex]\left \{ -4,-2,2,4 \right \}[/tex]

To find: the function that has domain [tex]\left \{ -4,-2,2,4 \right \}[/tex]

Solution:

A function is a relation in which every element of the domain has a unique image in the co-domain.

For x = 2, domain is [tex]\left \{2 \right \}\neq \left \{ -4,-2,2,4 \right \}[/tex]

For a line that passes through [tex](-2,-2)\,,\,(0,-3)[/tex],

domain must have 0 but [tex]0\notin \left \{ -4,-2,2,4 \right \}[/tex]

Domain of [tex]\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}[/tex] is [tex]\left \{ -4,-2,2,4 \right \}[/tex]

Domain of [tex]\left \{ (1, -4), (0, -2), (2, 2), (6, 4) \right \}[/tex] is [tex]\left \{ 1,0,2,6 \right \} \neq \left \{ -4,-2,2,4 \right \}[/tex]

So, answer is [tex]\left \{ (-4, 2), ( -2, 1), (2, 0), (4, 5) \right \}[/tex]

Answer:

its c

Step-by-step explanation: