Answer:
Step-by-step explanation:
we have
[tex]a- \frac{5}{a} + 4 = \frac{5}{4}[/tex]
we multiple both sides by (4a)
[tex]4a^{2} -20+ 16a= 5a\\4a^{2} + 11a - 20=0[/tex]
The delta = 11^2 - 4*4*(-20)= 121 + 320= 441= 21^2
These 2 solutions are:
[tex]x_{1}=\frac{-11+ 21}{4*2} =\frac{10}{8} =\frac{5}{4} \\x_{2}=\frac{-11 - 21}{4*2} =\frac{- 32}{8} = - 4[/tex]
Solution: - 4 , 5/4
But maybe you wrote:
[tex]\frac{a-5}{a+4}=\frac{5}{4} \\ 4(a-5)=5(a+4)\\4a -20= 5a+ 20\\4a-5a= 20 + 20\\-a = 40\\or\\ a= -40\\[/tex]
So a = -40
P.S: Pay attention to using parentheses
