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A 0.018-in-diameter glass tube is inserted into mercury, which makes a contact angle of 140° with glass. Determine the capillary drop of mercury in the tube at 68°F. Answer: 0.874 in. Use:
Density of mercury 847 lbm/ft3 at 77 0F, however, this can also be used for 68 0F. Surface tension of mercury glass in atmospheric air at 68 0F is 0.03015 lbf/ft.

Respuesta :

The capillary drop of mercury in the tube at 68°F is; 0.874 in.

We are given;

  • Diameter of glass tube; d = 0.018 in
  • Radius; r = d/2 = 0.018/2 = 0.009 in = 0.0002286 m
  • Contact angle; θ = 140°
  • Density; ρ = 847 lbm/ft³ = 13600 kg/m³
  • Surface tension; S = 0.03015 lbf/ft = 0.44 N/m

Formula for height of capillary drop due to surface tension is;

h = (2S*cosθ)/(rρg)

Plugging in the relevant values gives;

h = (2 * 0.44 * -0.7660)/(0.0002286 * 13600 * 9.8)

h = -0.022124 m

Converting to inches gives us approximately;

h = -0.874 inches

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