Answer:
Yes it was
two generations
Explanation:
H0: population is in Hardy-Weinberg equilibrium
Ha: population is not in Hardy-Weinberg equilibrium
P(S1) = (2×obs(S1S1) + obs(S1S2))/(2×fish(S1S1)+2×fish(S1S2) +2×fish(S2S2) )
P(S1)= (60+50)/(60+100+40)
P(S1)=0.55
P(S2)= 1-P(S1)
P(S2)= 0.45
Exp(S1S1)= 0.55×0.55×100=30.25
Exp(S1S2)= 2×0.45×0.55×100=49.5
Exp(S2S2)= 0.45×0.45×100=20.25
x²=∑ (Observed-Expected)²/ Expected
= (30-30.25)²/30.25 + (50-49.5)²/49.5+ (20-20.25)²/20.25
= 0.010203
The value at 5% significance level and degree of freedom 1 from table is 3.84. Since x² value is less than value we accept null hypothesis
It takes two generations to achieve Hardy-Weinberg equilibrium if conditions of Hardy-Weinberg are met.