Answer:
K= 25.16%
Mn= 34.59%
O= 40.25%
Explanation:
[tex]KMnO_4[/tex]
Find the total mass of the compound. You can do this by multiplying by the molar mass.
[tex]K=40*1=40\\Mn=55*1=55\\O=16*4=64[/tex]
add them:
40+55+64=159g
Now convert each element individually to grams using molar mass
[tex]1molK(\frac{40gK}{1molK} )=40gK[/tex]
[tex]1molMn(\frac{55gMn}{1molMn} )=55gMn[/tex]
[tex]4molO(\frac{16gO}{1molO})=64gO[/tex]
Divide by the mass of the compound and multiply by 100
[tex]K=\frac{40g}{159g} *100=25.16[/tex]
[tex]Mn=\frac{55g}{159g}*100=34.59[/tex]
[tex]O=\frac{64g}{159g}*100=40.25[/tex]
