How many solutions will each system of linear equations have? Match the systems with the correct number of
solutions.
y = x + 6 and 3x - 3y = -18
no solution
y = -2x + 5 and 2x + y = -7
Ano
infinitely many solutions
y = --4x + 11 and 6x + y = 11
one solution

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Answer:

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- Ripper

Step-by-step explanation:

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Based on the information given, the correct options will be:

  • y = x + 6 and 3x - 3y = -18 .... Infinitely many solutions.
  • y = -2x + 5 and 2x + y = -7 .... No solution.
  • y = -4x + 11 and -6x + y = 11 ... One solution.

Solving equations

y = -4x + 11 ....... equation i

-6x + y = 11 ...... equation ii

Put equation i into ii.

-6x + y = 11

-6x + (-4x + 11) = 11

-6x - 4x + 11 = 11

-6x - 4x = 11 - 11

-10x = 0

x = 0

Therefore, x = 0 and y = 11. This gives a solution for each variable.

y = -2x + 5 ..... i

2x + y = -7 ..... ii

Put equation i into ii

2x + y = -7

2x + (-2x + 5) = -7

2x - 2x = -7 - 5

0 = -12

This indicates no solution.

y = x + 6 ..... i

3x - 3y = -18 ..... ii

Put equation i into ii

3x - 3y = -18

3x - 3(x + 6) = -18

3x - 3x - 18 = -18

3x - 3x = - 18 + 18

0 = 0

This implies that there are infinitely many solutions.

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