The number of miles on car A is 50 more miles than the number of miles on car B and the number of miles on car B is 30 more miles more than the number of miles on car C all the cars travel 50 miles in 1 hour after 1 hour twice the number of miles no car A is 70 miles les than 3 times the number of miles of miles on car C how many miles were there on car b initially

The correct answer here is that there were originally 60 miles on car B. We can work this out with the following equation -

A = B - 50B = C + 30A + 50 = BB+ 50 = C + 802A = 3C - 70

Solution: A = 110, B = 60, C = 30

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wh62644 wh62644 · Answer 2 · 2020-10-20T20:45:30+02:00

Answer: 60 miles initially on car b

Step-by-step explanation:

The number of miles on Car A is 50 miles more than the number of miles on Car B,

a = b+50

and the number of miles on Car B is 30 miles more than the number of miles on Car C.

c = b-30

All the cars travel 50 miles in 1 hour.

All travel at 50 mph

After 1 hour, twice the number of miles Car A is 70 miles less than 3 times the number of miles on Car C.

2(a+50) = 3(c+50) - 70

2a + 100 = 3c + 150 - 70

2a = 3c + 150 - 70 - 100

2a = 3c - 20

Replace a with (b+50), replace c with (b-30)

2(b+50) = 3(b-30) - 20

2b + 100 = 3b - 90 - 20

2b + 100 = 3b - 110

2b = 3b - 110 - 100

2b = 3b - 210

210 = 3b - 2b

b = 210 mi car B initially

then

a = 210 + 50

a = 260 car A initially

and

c = 210 - 30

c = 180 mi Car C initially