Answer:
[tex]\frac{3}{4}a-\frac{1}{2}b-3[/tex]
Step-by-step explanation:
Given the expressions: [tex]4 -\frac{2}{3}b+\frac{1}{4}a $ and $ \frac{1}{2}a + \frac{1}{6}b - 7.[/tex]
We add:
[tex]4 -\frac{2}{3}b+\frac{1}{4}a + \frac{1}{2}a + \frac{1}{6}b - 7\\\\$First, we reorder the terms$\\\\=4 - 7-\frac{2}{3}b+ \frac{1}{6}b+\frac{1}{4}a + \frac{1}{2}a \\\\=-3+(\frac{1}{6}-\frac{2}{3})b+(\frac{1}{4}+\frac{1}{2})a\\\\=-3-\frac{1}{2}b+\frac{3}{4}a\\\\=\frac{3}{4}a-\frac{1}{2}b-3[/tex]
Answer:
3/4a-1/2b-3
Step-by-step explanation:
i am right b/c i just took the test
