messi1037
contestada

A rectangle has a perimeter of 64.
Let x equal the width of the rectangle.
Let y equal the area of the rectangle.

Which equation can be used to find the area of the rectangle?
A. y = x² - 64x
B. y = -x² + 64x
C. y = x² - 32x
D. y = -x²+ 32x​

Respuesta :

rigneshclient005

Answer:

You can use option (D) to find the area of rectangle

(D) y = - x²+32x

Step-by-step explanation:

If you can substitute your values you can find your answer

THANK YOU....

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ashishdwivedilVT

The expression for the given rectangle with width x and area y is[tex]y = -x^{2} +32[/tex]

it is given that

area of the rectangle = y

width of the rectangle = x

so the length of the rectangle will be = area/width = [tex]\frac{y}{x}[/tex]

perimeter = 64

What is the perimeter of a rectangle?

Perimeter is the sum of all four sides of the rectangle.

we can say that,

2(length + breadth) = 64

[tex]2( \frac{y}{x} + x)=64\\\\[/tex]

[tex]\frac{y}{x} + x= 32[/tex]

[tex]\frac{y + x^{2} }{x} = 32[/tex]

[tex]y+x^{2} = 32x[/tex]

[tex]y = -x^{2} +32[/tex]

therefore, the expression for the area of the rectangle,

[tex]y = -x^{2} +32[/tex]

to get more about rectangles refer to the link,

https://brainly.com/question/25292087

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