1. When the 12-Volts battery is used in the electrical circuit instead of the 6-Volts battery: C. The current is doubled.
2. The action which can produce an electric current in a loop of wire is: D. moving a magnet up and down near the wire.
3. The claim which is best supported by the student’s investigation is: A. An electric current in the wire produces a magnetic field.
4. The student should label the x-axis of the graph of the amount of electrical force between two charged particles: D. Distance between Particles (m).
1. To calculate the magnitude of current in the electrical circuit, we would apply Ohm's law:
[tex]V = IR\\\\I=\frac{V}{R}[/tex]
Where:
- V is the voltage measured in Volts.
- I is the current measured in Ampere.
- R is the resistance measured in Ohms.
When V = 6-Volts and R = 24-Ohms:
[tex]I=\frac{6}{24}[/tex]
I = 0.25 Amp.
When V = 12-Volts and R = 24-Ohms:
[tex]I=\frac{12}{24}[/tex]
I = 0.50 Amp.
Therefore, the the magnitude of current in the electrical circuit is doubled.
2. The action which can produce an electric current in a loop of wire is the movement of a magnet up and down in proximity to the wire because the magnetic field would induce a current in accordance with Faraday's law of electromagnetic induction.
3. The claim which is best supported by the student’s investigation is that an electric current in the insulated wire produces a magnetic field and as such it would attract the steel paperclips.
4. In accordance with Coulombs law, the student should label the x-axis of the graph of the amount of electrical force between two charged particles as the distance between particles, which is measured in meters (m).
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