Answer:
Answer is option 2) 37
Step-by-step explanation:
[tex]area \: of \: the \: figure \\ =2( area \: of \: rectangle) + \: area \: of \: quadrant \\ = 2(lb) + \frac{\pi \: {r}^{2} }{4} \\ here \: l = 5 \: \: \: \: b = 3 \: \: \: and \: \: \: r = 3 \\ are \: of \: figure \\ = 2(5 \times 3) + \frac{\pi \: {3}^{2} }{4} \\ = (2 \times 15) + \frac{22}{7} \times \frac{9}{4} \\ = 30 + \frac{11}{7} \times \frac{9}{2} \\ = 30 + 7.07 \\ = 37.07 \\ area \: of \: the \: figure \: is \: \\
approximately
\: equal \: to \: 37 \: {cm}^{2} [/tex]
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