shanthielBo
contestada

A projectile is fired with an initial speed of 200 m/s, angle of elevation 60 degrees, and fired from 100m above the ground.

What is the range, maximum height, and speed at impact?

Respuesta :

d = v^2(sin2(theeta))/g
d = 200^2 sin2(60)/9.8
d = 40000(sin 120 )/9.8
d = 40000(0.5806)/9.8
d = 23224.44/9.8
d = 2369 m
s = vf^2 - vi^2
s = 0^2 - 200^2
s = 0 - 40000 m 
s = -40000 m (distance can never be negative )

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