Answer:
[tex](0, \frac{2}{3})[/tex]
Step-by-step explanation:
Given the system of equation:
2x + 3y = 2 ....[1]
x + 6y = 4 . ...[2]
Multiply by 2 to both sides in [1] we get;
4x + 6y =4 ....[3]
Subtract equation [2] from [3] to eliminate y we get;
[tex]4x-x = 0[/tex]
⇒[tex]3x = 0[/tex]
Divide both sides by 3 we have;
x = 0
Substitute the value of x in [1] we have;
2(0)+ 3y = 2
⇒[tex]0+3y =2[/tex]
⇒[tex]3y = 2[/tex]
Divide both sides by 3 we have;
[tex]y = \frac{2}{3}[/tex]
Therefore, the solution for the given system of equation is, [tex](0, \frac{2}{3})[/tex]
