Answer:
45.873 KN/mL is the ultimate bearing capacity of the foundation.
Explanation:
C' = 10.0 kN/m², Ф' = 25, r = 18 kN/m²
ration of Df/B ≤ 1 , Df ≤ B (1 ≤ 2.5m)
It is a shallow foundation
∴ Ultimate bearing Capacity
qu = C'[tex]N_c[/tex] + r[tex]D_F[/tex].[tex]N_q[/tex] + [tex]\frac{1}{2}[/tex]Br[tex]N_r[/tex]
NФ = tan²(45 + Ф/2)
= tan²(45 - 25/2)
= 0.41
Nq = NФ×e^(πtanФ') = 0.41e^(πtan25)
= 1.756
Nr = 1.8tanФ(Nq - 1) = 1.8tan25(1.756 - 1)
= 0.634
Nc = 1.621
putting the above values in equation.
qu = 45.873 KN/mL
