Respuesta :
Answer:
a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:
[tex] df = n-1= 10-1=9[/tex]
d.9
b) [tex]s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15[/tex]
a.15
c) For this case we have the sample size n = 25 and the sample variance is [tex]s^2 =400[/tex] , the standard error can founded with this formula:
[tex] SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80[/tex]
Step-by-step explanation:
Part a
For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:
[tex] df = n-1= 10-1=9[/tex]
d.9
Part b
From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:
[tex]SS = \sum_{i=1}^n (X_i -\bar X)^2[/tex]
And the sample variance for this case can be calculated from this formula:
[tex]s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15[/tex]
a.15
Part c
For this case we have the sample size n = 25 and the sample variance is [tex]s^2 =400[/tex] , the standard error can founded with this formula:
[tex] SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80[/tex]
