Answer:
The angle of depression of the slide is [tex]5.2^o[/tex]
Explanation:
Given the length of vertical drop, i.e., the perpendicular is 36.3 yards
Length of water slide is 400 yards
A slide is always slanted, therefore, it will be considered as the hypotenuse
Therefore, hypotenuse = 400 yards
Let the angle of depression be [tex]\theta[/tex]
[tex]\sin \theta=\frac{\text { perpendicular }}{\text { hypotenuse }}[/tex]
substituting the values,
[tex]\sin \theta=\frac{36.3}{400}=0.09075[/tex]
[tex]\theta=\sin ^{-1}(0.09075)[/tex]
[tex]\theta= 5.2^{\circ}[/tex]
Hence, the angle of depression is [tex]5.2^o[/tex]
