Answer:
The composition of benzene is 0.77 and the composition of toluene is 0.23
Explanation:
The Raoult´s law is:
[tex]P=P_{A} ^{o} x_{A} +P_{B} ^{o} x_{B}[/tex]
Where
P = total pressure of solution benzene-toluene
PA⁰= vapor pressure of benzene = 95 torr
PB⁰ = vapor pressure of toluene = 28 torr
xA = mole fraction of benzene
xB = mole fraction of toluene
[tex]x_{A} +x_{B} =1\\x_{A}=x_{B}\\Replacing\\x_{A}=0.5\\x_{B}=0.5[/tex]
The total pressure of the solution is:
[tex]P=(95*0.5)+(28*0.5)=61.5torr[/tex]
The composition of benzene and toluene:
[tex]Benzene=\frac{P_{A}^{o} }{P} =\frac{95*0.5}{61.5} =0.77\\Toluene=\frac{P_{B}^{o} }{P} =\frac{28*0.5}{61.5} =0.23[/tex]
