Respuesta :

Explanation:

Since methane gas is at 1 atm and 273 K, it is at standard temperature and pressure(STP).

One mole of every gas occupies 22.4 dm^3 at STP, and vice versa. So,

22.4 dm^3 at STP of CH4=1 mol=12+4(1)=16 g

0.462 L(0.462 dm^3) at STP of CH4

=(16 g×0.462 dm^3)/22.4 dm^3

=0.33 g