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The following reaction was carried out in a 3.75 L reaction vessel at 1100 K: C(s)+H2O(g)⇌CO(g)+H2(g) If during the course of the reaction, the vessel is found to contain 6.50 mol of C, 15.9 mol of H2O, 3.20 mol of CO, and 8.20 mol of H2, what is the reaction quotient Q?

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Answer:

Reaction quotient, Q, is 0.44

Explanation:

For the reaction:

C(s)+H₂O(g) ⇌ CO(g)+H₂(g)

Reaction quotient Q, at any course of the reaction, is defined as:

Q = [CO][H₂] / [H₂O]

Concentration of reactants is:

[CO] = 3.20mol / 3.75L = 0.853M

[H₂] = 8.20mol / 3.75L = 2.187M

[H₂O] = 15.9mol / 3.75L = 4.24M

Replacing, Q is:

Q = [0.853][2.187] / [4.24]

Q = 0.44

The branch of science which deals with the chemical bond is called chemistry.

The reaction quotient(Q) is 0.44

The reaction in the question is as follows:-

[tex]C(s)+H_2O(g)--->< CO(g)+H_2(g)[/tex]

The formula we used is as follows;-

[tex]Q = \frac{[CO][H_2] }{ [H_2O]}[/tex]

The data is given in the question is as follows:-

  • [CO] = 3.20mol / 3.75L = 0.853M
  • [H₂] = 8.20mol / 3.75L = 2.187M
  • [H₂O] = 15.9mol / 3.75L = 4.24M

Putting the value in the equation, we will get.

[tex]Q = \frac{[0.853][2.187]}{ [4.24]}\\\\Q = 0.44[/tex]

The correct answer is 0.44

For more information, refer to the link;-

https://brainly.com/question/22810476

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